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12 Wind Energy
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have never met something so fast before. For a modern derivation of the Betz limit and how efficiency depends on tip speed, see 1. The largest turbines having 150 m diameter rotors are rated for up to 10 MW of electrical power production.
Example 12.2.1 How much power could you expect a small (4 m diameter) 3-blade wind turbine situated atop your house to deliver in a respectable 5 m/s breeze?
The radius is 2 m and we’ll pick a middle-of-the-road efficiency of 45%; P=0.45
0.45. (1.25 kg/m3) 7 (2m)2. (5 m/s)3 comes to about 450 W 14
Besides the limit on how much power can be pulled out of the air by a single turbine, we also find limits on how densely they may be populated in a given area: how much space is required between turbines so that one does not disrupt the other. Obviously, it would not serve to put one turbine directly behind another, as they would at best split the available power arriving as wind. Even side by side, it is best to leave room between windmills so that additional rows are not deprived of wind power. A rule of thumb is to separate turbines by at least 5-8 diameters side-to-side, and 7-15 diameters15 along the (prevailing) wind direction. For the sake of illustration, Figure 12.5 shows a spacing on the denser side of the range, but otherwise we adopt the more recent recommendations and use 8 diameters side-to-side and 15 diameters deep [^75]. This works out to a 0.65% “fill factor,” meaning that 0.65% of the land area contains an associated rotor cross section.”
rotor (viewed from above)
prevailing wind direction
10D
16
5D
In order to compare to other forms of renewable energy, we can evaluate
a power per unit land area (in
12 Wind Energy 190 wind is not always blowing, and its speed varies over wide ranges. this sense, wind is an intermittent power source. Just as for hydroelectric installations, wind resources are characterized by a regionally-dependent capacity factor, which is the ratio of energy delivered to what would have been delivered if the generation facility operated at full capacity at all times. Typical capacity factors for wind in the U.S.18 are around 33%, and Figure 12.6 provides a visual sense for how this manifests in the real world: pretty erratic. 0.5 1 01-Oct-2007 M 08-Oct-2007 15-Oct-2007 MM MMA J 22-Oct-2007 29-Oct-2007 For very low wind speeds,5 wind turbines do not have enough wind to turn at all and sit still at zero output. Furthermore, a turbine is rated at some maximum power output, which occurs at some moderately high wind speed,6 beyond which the generator risks damage-like “redlining” a car’s engine. When the wind climbs above this maximumrated speed, the turbine is pegged at its maximum power-no longer following a v3 relation and deliberately twists its blades21 to be less efficient as the wind speed grows so that it maintains constant (maximum) power output. When the wind speed becomes large enough to endanger the turbine, it will twist its blades parallel to the wind to allow the air to pass without turning the rotor at all, so that it no longer spins while it “rides out” the high winds.7
Figure 12.7: Actual data (thickly-clustered black circles) of power delivered by a turbine rated at 2 MW, as a function of wind velocity. The red curve represents the theoretical Betz limit of 59%, appearing as a cubic function of velocity-as Eq. 12.2 dictates. The better-matching blue curve corresponds to an overall efficiency & = Cp = 0.44 (44%), and the green curve-which rolls over from the cubic function and saturates at higher velocities-is the manufacturer’s expectation for the unit 4. The “cut-in” velocity for this turbine is around 3.5 m/s: note the small step up from zero output in the green curve. This turbine saturates around 12 m/s: the green curve flattens out and no black circles appear above the cutoff. From ©2017 Wiley.
12.3 Wind Installations
24 Global wind installations are rising rapidly, currently (as of 2020) above 600 GW of installed capacity.8 Table 12.2 lists the major players, in terms of installed capacity, average generation, fraction of total energy, capacity factor, and share of global wind generation. The amount of wind energy in each country depends on a combination of how much wind is available in the country, how fast electricity demand is growing, electrical infrastructure, and political interest in renewable energies.
Table 12.2: Global wind installations in 2018 [[^78] [^79] [^80] [^81] [^82] [^83] [^84]]. The top six countries capture 85% of the global total.
Country GW installed GW average cap. fac. (%) energy fraction (%) global share (%) China 184 41.8 22.7 3.0 33 U.S. 97 31.4 32.4 2.7 25 Germany 59 12.7 21.4 8.3 10 India 35 6.5 18.5 2.3 5.2 Spain 23 5.4 23.5 8.3 4.3 UK 21.7 6.5 30.0 6.9 5.2 World Total 592 125 21.1 2.0 100 0 2 8 4 6 Wind generation (GW) In 2018, the U.S. had about 94 GW of installed wind capability.9 This number has recently surpassed hydroelectric installed capacity (about 80 GW). Both are impacted by capacity factors, which for wind averages 33% in the U.S., while hydropower is just over 40%. The net effect is that the generation for the two is pretty comparable.10 Where is the wind power in the U.S. installed? Figure 12.8 shows that Texas wins, at 8.7 GW. Oklahoma is a distant second at 3.2 GW, Iowa at 2.5 GW. California is in fifth place at 1.6 GW. Figure 12.8: Wind power by state, in terms of average generation, in GW, in 2018. The color scale may seem unhelpful, but the unavoidable truth is that many states don’t have a lot going on, and Texas is so dominant as to render other states almost insignificant. A logarithmic color scale could help, but then the important lesson on the gross disparity might go unappreciated.
… as we also saw in Table 10.3 (p. 170)
0
5 10 15 20 Wind density (m
. about 10 times, in the case of Iowa, but bear in mind the 0.2
0.1 0.2 0.3 Wind capacity factor 0.4 12 Wind Energy 193 Figure 12.11: Capacity factor for wind installations by state (based on 2018 data).
12.4 Upshot: Wind is not Overblown
Wind has surged tremendously in the last decade (Fig. 7.5; p. 108), proving to be an economically viable and competitive resource. But how much could we expect to get from wind?
Putting a few of the previous results together, If the entire contiguous U.S. (area ~1013 m2) were developed for wind at an estimated power density of 0.2
- Wind is replenished on the planet daily by solar illumination;
12 Wind Energy 194
- Harnessing wind is relatively low-tech and straightforward; Wind has decent efficiency-typically 40-50%-in extracting energy from the oncoming wind; Life-cycle CO2 emissions for wind is only 2% that of traditional fossil fuel electricity 14; Growth in the wind sector points to economic viability; ▸ Wind is able to scale up to cover a meaningful fraction of energy demand. And the downsides: Wind is intermittent: power when nature allows, not when people demand; Wind is regionally variable: many places do not produce enough wind to support development; ▸ Wind can cause environmental disruption to habitats especially dangerous to birds and bats; Esthetic objections to noise and degradation of scenery hamper expansion.
12.5 Problems
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A modest slap32 might consist of about 1 kg of mass moving at 2 m/s. How much kinetic energy is this?
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A hard slap might consist of about 1 kg of mass moving at 10 m/s. How much kinetic energy is this, and how much warmer would 10 g of skin33 get if the skin has the heat capacity properties of water, as in the definition of a calorie (Sec. 5.5; p. 73 and Sec. 6.2; p. 85 are relevant)?
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A 10 kg bowling ball falls from a height of 5 m. Using the convenient g≈ 10 m/s2, how much gravitational potential energy does it have? Just before it hits the ground, all of this potential energy has gone into kinetic energy.[^34] What is the speed of the bowling ball when it reaches the ground, based on kinetic energy?
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Did the final answer for the speed of the bowling ball at the end of its drop depend on the mass?35 Write out the math symbolically36 and solve for velocity, v. Does the result depend on mass?
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Thermal energy is just randomized kinetic energy on a microscopic scale. To gain some insight into this, consider one liter (1 kg) of water, and figure out how much energy it would take to heat it from absolute zero temperature37 to 300 K assuming that the definition of the calorie (Sec. 5.5; p. 73) applies across this entire range. If this same amount of energy went into kinetic energy-hurling the water across the room-what would the corresponding velocity be? 32:… how painful can a few Joules be? 33: … corresponding to a volume of 10 mL appropriate to a slap area of 10 cm by 10 cm and to a depth of 1 mm 34: … neglecting any energy flow to air resistance 35: Try it using a different mass. 36: … using variables/symbols 37: …0 K, when the kinetic energy is effectively frozen out, or stopped As large as the number is, it is representative of the speeds of individual molecules within the water, and is, not coincidentally, similar to the speed of sound in water.
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A typical house may have a floor area around 150 m2 (1,600 square feet). If the floor-to-ceiling distance is typically 2.5 m, how much mass is in the air within the house? Could you lift this much mass if handed to you as bags of rocks?
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Atmospheric pressure is about 105 N/m2, meaning that a 100,000 N weight of air-corresponding to a mass of 10,000 kg-sits atop very square meter of the ground (at or near sea level). If the air density were constant at 1.25 kg/m3-rather than decreasing with height as it actually does how high would the atmosphere extend to result in this weight (mass)?
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Comparing the pale green region in the southeastern U.S. to the purple region of the plains states in Figure 12.2, how much more power would we expect out of the same rotor placed in the plains than in the southeast (by what factor is it bigger in the plains)?
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How much more powerful is a hurricane-strength wind of 50 m/s hitting your house than is a light breeze of 5 m/s?
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How much power would a moderate-sized 50%-efficient wind turbine produce whose radius is 10 m at wind speeds of 5 m/s, 10 m/s, 15 m/s, and 20 m/s? Express the answers in kW or MW, depending on what is most natural.
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The Betz limit says that we get to keep no more than 59% of the available wind power. If 59% of the kinetic energy in a lump of air moving at speed 38 v is removed, how fast is it going afterwards,3 as a fraction of the original speed? 39
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The largest wind turbines have rotor diameters40 around 150 m. Using a sensible efficiency of 50%, what power does such a jumbo turbine deliver at a maximum design wind speed of 13 m/s?
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A recent news article announces the largest wind turbine yet, measuring 220 m in diameter and having a maximum power output of 13 MW. Using a reasonable efficiency, calculate the velocity of the wind at which maximum power is reached.
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Compare the tip speed of a three-blade turbine operating at its optimal efficiency (as per Figure 12.4) in a moderate wind of 7 m/s to typical freeway driving speeds in the same units.
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Traveling down the road, you carefully watch a three-bladed wind turbine, determining that it takes two seconds to make a full revolution. Assuming it’s operating near the peak of its efficiency curve11 according to Figure 12.4, how fast do you infer the wind speed to be if the blade length+2 appears to be 15 m long? 42
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Building from the result in Problem 15, how much power is this windmill delivering if its efficiency is about 50%? 12 Wind Energy 195 This is called the scale height of the atmosphere, ho, which you may wish to compare to the tallest mountains on Earth or the height at which airplanes fly. The actual density of the atmosphere decreases exponentially as a function of height, with ho being the characteristic scale. 38: Make up your own velocity or solve in symbols/variables: same either way. 39: This relates to wind speed just behind a wind turbine 40: not radius 41: Hint: focus on tip speed. 42: … corresponding to radius of the rotor Reflect on the fact that just estimating the rotor blade length and timing its revolution is enough for you to produce an estimate of power being generated!
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In a way similar to Figure 12.5, replicate the statement in the text that the fraction of land covered per rotor area is 0.65% if turbines are separated by 15 rotor diameters along one direction and 8 rotor diameters along the cross direction.
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Check that the units of Eq. 12.343 indeed are equivalent to Watts per square meter (
). -
Provide a clear explanation of why the area under the blue curve in Figure 12.6 compared to the area of the whole rectangular box is an appropriate way to assess the capacity factor of the depicted wind farm?
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What capacity factor would you estimate for the wind farm performance depicted in Figure 12.6? In other words, what is the approximate area under the curve compared to the entire box area, as explored in Problem 19? An approximate answer is fine.
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Referring to Figure 12.7, examine performance at 5 m/s and at 10 m/s, picking a representative power for each in the middle of the cluster of black points, and assigning a power value from the left-hand axis. What is the ratio of power values you read off the plot, and how does this compare to theoretical expectations for the ratio going like the cube of velocity?
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Figure 12.7 surprisingly has all the information required to deduce the rotor diameter! The turbine appears to produce 1,400 kW when the wind velocity is 10 m/s, and we also know it appears to operate at ε = 0.44. What is the rotor diameter?
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Considering that wind turbines are rated for the maximumtolerable wind speed around 12 m/s, and tend to operate at about 30% capacity factor, how much average power44 would a 100 m diameter turbine operating at 45% efficiency be expected to produce?
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Table 12.2 shows Germany having more than twice the wind capability as Spain, yet each gets 8.3% of its power from wind. What do you infer the difference to be between the countries? 12 Wind Energy 43: …essentially pv3 196 44: Hint: compute power at 12 m/s then apply capacity factor Hint: no external research necessary: what do the numbers mean?
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Ragheb et al. (2011), “Wind Turbines Theory - The Betz Equation and Optimal Rotor Tip Speed Ratio” ↩︎ ↩︎
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Not only is the three-blade design the most efficient, its lower tip speed is less dangerous than for 2 or 1-blade designs, according to Figure 12.4. ↩︎
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Recall that this choice gave sensible global wind power estimates lining up with Table 10.2 (p. 168). ↩︎
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Fischer et al. (2017), “Statistical learning for windpower: a modeling and stability study towards forecasting"demonstrates the aspects covered in the previous paragraph: “cutting in” just above 3 m/s and maxing out (saturating) beyond about 12 m/s. In between, it closely follows a cubic function at an overall efficiency of 44% (blue curve). 12 Wind Energy 191 ↩︎ ↩︎
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. less than about 3 m/s; called the “cut-in” velocity ↩︎
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… usually around 12-15 m/s ↩︎
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A typical shut-off wind speed for turbines is 20-30 m/s. 1500 2000 Electrical power [kW] 1000 500 0 T 0 5 10 Cp=16/27 ■ Cp=0.44 Wind speed [m.s1] Builder curve 15 20 Figure 12.7 shows a typical power curve for a 2 MW turbine, on top of which are drawn a cubic function of velocity at the theoretical Betz limit (red curve), a cubic (blue) at 44% efficiency (ε = 0.44), and the green manufacturer’s curve 4. Notice that the turbine performance ↩︎
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A small fraction of this is realized, due to the capacity factor. ↩︎
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From tables 1.14.B and 6.2.B in [^85] ↩︎
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Lack of wind makes it a poor fit: see also Figure 12.2. ↩︎
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Castro et al. (2011), “Global Wind Power Potential: Physical and Technological Limits” ↩︎
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(2020), Life Cycle GHG Emissions ↩︎